What is the answer to log_{2}(16)=8*2^{-x} ?

The answer to log_{2}(16)=8*2^{-x} is x=1

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log_{2}(16)=8*2^{-x}

lo g_{2} (16) = 8 \cdot 2^{- x}

x = 1

Solution steps

lo g_{2} (16) = 8 \cdot 2^{- x}

Switch sides

8 \cdot 2^{- x} = lo g_{2} (16)

Divide both sides by

8

2^{- x} = \frac{1}{2}

Apply exponent rules

- x = - 1

Solve

- x = - 1 : x = 1

x = 1

100 \cdot 2^{4 x} = 15

x, e^{x y} = 0

3 e^{4 x + 1} = 2

9^{3 x + 2} = \frac{1}{3 ^{2 x - 5}}

2^{- 2 x} + 2^{- x} = 2

What is the answer to log_{2}(16)=8*2^{-x} ?
The answer to log_{2}(16)=8*2^{-x} is x=1
Solve for x: log_{2}(16)=8*2^{-x}
The solution is x=1