What is the answer to 2^{8^{x-2}}=4^{4^{x+1}} ?

The answer to 2^{8^{x-2}}=4^{4^{x+1}} is x=9

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2^{8^{x-2}}=4^{4^{x+1}}

2^{8^{x - 2}} = 4^{4^{x + 1}}

x = 9

Solution steps

2^{8^{x - 2}} = 4^{4^{x + 1}}

Apply exponent rules

3 (x - 2) = 1 + 2 (x + 1)

Solve

3 (x - 2) = 1 + 2 (x + 1) : x = 9

x = 9

e^{3 x} = \frac{e ^{2}}{e ^{x}}

3^{y} = 6

7^{x} = 3^{x + 4}

4 e^{x} = 100

What is the answer to 2^{8^{x-2}}=4^{4^{x+1}} ?
The answer to 2^{8^{x-2}}=4^{4^{x+1}} is x=9
Solve for x: 2^{8^{x-2}}=4^{4^{x+1}}
The solution is x=9