What is the answer to 2^{6x+7}=(1/8)^{1-5x} ?

The answer to 2^{6x+7}=(1/8)^{1-5x} is x= 10/9

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2^{6x+7}=(1/8)^{1-5x}

2^{6 x + 7} = (\frac{1}{8})^{1 - 5 x}

x = \frac{10}{9}

Decimal Notation

x = 1.11111 \dots

Solution steps

2^{6 x + 7} = (\frac{1}{8})^{1 - 5 x}

Apply exponent rules

6 x + 7 = - 3 (1 - 5 x)

Solve

6 x + 7 = - 3 (1 - 5 x) : x = \frac{10}{9}

x = \frac{10}{9}

5^{x + 1} = 3^{2 x}

4^{x + 1} - 32 = 0

1 2^{x - 1} = 1500

2 \cdot 2^{x} + 4^{x} = 80

e^{x} = \frac{4}{x}

What is the answer to 2^{6x+7}=(1/8)^{1-5x} ?
The answer to 2^{6x+7}=(1/8)^{1-5x} is x= 10/9
Solve for x: 2^{6x+7}=(1/8)^{1-5x}
The solution is x= 10/9