What is the answer to 3^{2x-1}=17 ?

The answer to 3^{2x-1}=17 is x=(ln(51))/(2ln(3))

Solve for x: 3^{2x-1}=17

The solution is x=(ln(51))/(2ln(3))

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3^{2 x - 1} = 17

x = \frac{ln ( 51 )}{2 ln ( 3 )}

Decimal Notation

x = 1.78945 \dots

Solution steps

3^{2 x - 1} = 17

Apply exponent rules

(2 x - 1) ln (3) = ln (17)

Solve

(2 x - 1) ln (3) = ln (17) : x = \frac{ln ( 51 )}{2 ln ( 3 )}

x = \frac{ln ( 51 )}{2 ln ( 3 )}

x, e^{7 - 4 x} = 6

2^{3 x + 5} = 6 4^{x - 7}

e^{2 x} - 8 e^{x} + 15 = 0

200 = 100 e^{r \cdot 6}

2^{x} = 24

What is the answer to 3^{2x-1}=17 ?
The answer to 3^{2x-1}=17 is x=(ln(51))/(2ln(3))
Solve for x: 3^{2x-1}=17
The solution is x=(ln(51))/(2ln(3))