What is the answer to 4^{2x+1}=6^{x+3} ?

The answer to 4^{2x+1}=6^{x+3} is x=(ln(54))/(ln(8/3))

Solve for x: 4^{2x+1}=6^{x+3}

The solution is x=(ln(54))/(ln(8/3))

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4^{2 x + 1} = 6^{x + 3}

x = \frac{ln ( 54 )}{ln ( \frac{8}{3} )}

Decimal Notation

x = 4.06695 \dots

Solution steps

4^{2 x + 1} = 6^{x + 3}

Apply exponent rules

(2 x + 1) ln (4) = (x + 3) ln (6)

Solve

(2 x + 1) ln (4) = (x + 3) ln (6) : x = \frac{ln ( 54 )}{ln ( \frac{8}{3} )}

x = \frac{ln ( 54 )}{ln ( \frac{8}{3} )}

6 4^{- 2 x - 1} \cdot 8^{4 x} = 1 6^{2 x}

7^{3 x - 2} = 7^{- 2 x + 8}

e^{2 - 4 x} = 9

7^{3 - 5 x} = (\frac{1}{49})^{2 x + 9}

9^{x} = \frac{1}{27}

What is the answer to 4^{2x+1}=6^{x+3} ?
The answer to 4^{2x+1}=6^{x+3} is x=(ln(54))/(ln(8/3))
Solve for x: 4^{2x+1}=6^{x+3}
The solution is x=(ln(54))/(ln(8/3))