What is the answer to (4)5^{3-x}-7=2 ?

The answer to (4)5^{3-x}-7=2 is x=(-ln(9/4)+3ln(5))/(ln(5))

Solve for x: (4)5^{3-x}-7=2

The solution is x=(-ln(9/4)+3ln(5))/(ln(5))

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(4) 5^{3 - x} - 7 = 2

x = \frac{- ln ( \frac{9}{4} ) + 3 ln ( 5 )}{ln ( 5 )}

Solution steps

(4) \cdot 5^{3 - x} - 7 = 2

Move

7

to the right side

4 \cdot 5^{3 - x} = 9

Divide both sides by

4

5^{3 - x} = \frac{9}{4}

Apply exponent rules

(3 - x) ln (5) = ln (\frac{9}{4})

Solve

(3 - x) ln (5) = ln (\frac{9}{4}) : x = \frac{- ln ( \frac{9}{4} ) + 3 ln ( 5 )}{ln ( 5 )}

x = \frac{- ln ( \frac{9}{4} ) + 3 ln ( 5 )}{ln ( 5 )}

4^{x} = 5^{2 x + 1}

x^{x^{3}} = 2^{2}

x, e^{x} + e^{- x} = 3

k, n = 2^{k}

3^{x} = 19

What is the answer to (4)5^{3-x}-7=2 ?
The answer to (4)5^{3-x}-7=2 is x=(-ln(9/4)+3ln(5))/(ln(5))
Solve for x: (4)5^{3-x}-7=2
The solution is x=(-ln(9/4)+3ln(5))/(ln(5))