What is the answer to 7^{2x-3}=5^x ?

The answer to 7^{2x-3}=5^x is x=(3ln(7))/(2ln(7)-ln(5))

Solve for x: 7^{2x-3}=5^x

The solution is x=(3ln(7))/(2ln(7)-ln(5))

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7^{2 x - 3} = 5^{x}

x = \frac{3 ln ( 7 )}{2 ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = 2.55773 \dots

Solution steps

7^{2 x - 3} = 5^{x}

Apply exponent rules

(2 x - 3) ln (7) = x ln (5)

Solve

(2 x - 3) ln (7) = x ln (5) : x = \frac{3 ln ( 7 )}{2 ln ( 7 ) - ln ( 5 )}

x = \frac{3 ln ( 7 )}{2 ln ( 7 ) - ln ( 5 )}

2 7^{x} = 3

100 0^{8} = 1 0^{w}

5^{4 x + 1} = 4^{3 x + 2}

x, 8^{x} = 3

- e^{x} = 0

What is the answer to 7^{2x-3}=5^x ?
The answer to 7^{2x-3}=5^x is x=(3ln(7))/(2ln(7)-ln(5))
Solve for x: 7^{2x-3}=5^x
The solution is x=(3ln(7))/(2ln(7)-ln(5))