What is the answer to 5^{2x+1}=6^{x-2} ?

The answer to 5^{2x+1}=6^{x-2} is x=-(ln(180))/(2ln(5)-ln(6))

Solve for x: 5^{2x+1}=6^{x-2}

The solution is x=-(ln(180))/(2ln(5)-ln(6))

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5^{2 x + 1} = 6^{x - 2}

x = - \frac{ln ( 180 )}{2 ln ( 5 ) - ln ( 6 )}

Decimal Notation

x = - 3.63877 \dots

Solution steps

5^{2 x + 1} = 6^{x - 2}

Apply exponent rules

(2 x + 1) ln (5) = (x - 2) ln (6)

Solve

(2 x + 1) ln (5) = (x - 2) ln (6) : x = - \frac{ln ( 180 )}{2 ln ( 5 ) - ln ( 6 )}

x = - \frac{ln ( 180 )}{2 ln ( 5 ) - ln ( 6 )}

e^{2 l n (x)} = 9

4 \cdot 1 0^{- 3 x} = 18

2^{x - 1} = 16

3^{x^{2} - 3 x} = 81

1 6^{2 p} = 3 2^{p + 3}

What is the answer to 5^{2x+1}=6^{x-2} ?
The answer to 5^{2x+1}=6^{x-2} is x=-(ln(180))/(2ln(5)-ln(6))
Solve for x: 5^{2x+1}=6^{x-2}
The solution is x=-(ln(180))/(2ln(5)-ln(6))