What is the answer to 2^{2x}-2^{x+1}=-1 ?

The answer to 2^{2x}-2^{x+1}=-1 is x=0

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2^{2x}-2^{x+1}=-1

2^{2 x} - 2^{x + 1} = - 1

x = 0

Solution steps

2^{2 x} - 2^{x + 1} = - 1

Apply exponent rules

(2^{x})^{2} - 2^{x} \cdot 2^{1} = - 1

Rewrite the equation with

2^{x} = u

(u)^{2} - u \cdot 2^{1} = - 1

Solve

u^{2} - u \cdot 2^{1} = - 1 : u = 1

u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 1 : x = 0

x = 0

9^{x} - 4 (3^{x + 1}) + 27 = 0

2 = 1. 1^{x}

(1.045)^{x} = 2

3^{x - 1} = \frac{1}{81}

1 0^{1 - x} = 6^{x}

What is the answer to 2^{2x}-2^{x+1}=-1 ?
The answer to 2^{2x}-2^{x+1}=-1 is x=0
Solve for x: 2^{2x}-2^{x+1}=-1
The solution is x=0