What is the answer to 36^{(3x-1)}=6^{(4x+2)} ?

The answer to 36^{(3x-1)}=6^{(4x+2)} is x=2

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36^{(3x-1)}=6^{(4x+2)}

3 6^{(3 x - 1)} = 6^{(4 x + 2)}

x = 2

Solution steps

3 6^{(3 x - 1)} = 6^{(4 x + 2)}

Apply exponent rules

2 (3 x - 1) = 4 x + 2

Solve

2 (3 x - 1) = 4 x + 2 : x = 2

x = 2

(- e^{- k} + e^{\frac{- 5 k}{6}}) = 2

2^{2 x} = 16

(e^{4})^{x} e^{x^{2}} = e^{12}

6^{x} = 5

k, \frac{n}{2 ^{k}} = 1

What is the answer to 36^{(3x-1)}=6^{(4x+2)} ?
The answer to 36^{(3x-1)}=6^{(4x+2)} is x=2
Solve for x: 36^{(3x-1)}=6^{(4x+2)}
The solution is x=2