What is the answer to 3^x=2^{x-1} ?

The answer to 3^x=2^{x-1} is x=-(ln(2))/(ln(3)-ln(2))

Solve for x: 3^x=2^{x-1}

The solution is x=-(ln(2))/(ln(3)-ln(2))

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3^{x} = 2^{x - 1}

x = - \frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = - 1.70951 \dots

Solution steps

3^{x} = 2^{x - 1}

Apply exponent rules

x ln (3) = (x - 1) ln (2)

Solve

x ln (3) = (x - 1) ln (2) : x = - \frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

x = - \frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

5^{x} = 0.04

lo g_{3} (3^{2 x + 1}) = 15

1 6^{3^{2 x}} = 8^{4^{2 x}}

6^{x} = 36

2^{n} = 3600000

What is the answer to 3^x=2^{x-1} ?
The answer to 3^x=2^{x-1} is x=-(ln(2))/(ln(3)-ln(2))
Solve for x: 3^x=2^{x-1}
The solution is x=-(ln(2))/(ln(3)-ln(2))