What is the answer to 4^{0.2x}+6=43 ?

The answer to 4^{0.2x}+6=43 is x=(ln(37))/(0.4ln(2))

Solve for x: 4^{0.2x}+6=43

The solution is x=(ln(37))/(0.4ln(2))

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4^{0.2 x} + 6 = 43

x = \frac{ln ( 37 )}{0.4 ln ( 2 )}

Solution steps

4^{0.2 x} + 6 = 43

Move

6

to the right side

4^{0.2 x} = 37

Apply exponent rules

0.2 x ln (4) = ln (37)

Solve

0.2 x ln (4) = ln (37) : x = \frac{ln ( 37 )}{0.4 ln ( 2 )}

x = \frac{ln ( 37 )}{0.4 ln ( 2 )}

3^{- x} = 243

1 2^{x^{2} + 5 x - 4} = 1 2^{2 x + 6}

2 7^{x^{4}} = 9^{24}

\frac{1 0 ^{x} + 1}{1 + 1 0 ^{- x}} = 100

2 e^{2 x} = 0

What is the answer to 4^{0.2x}+6=43 ?
The answer to 4^{0.2x}+6=43 is x=(ln(37))/(0.4ln(2))
Solve for x: 4^{0.2x}+6=43
The solution is x=(ln(37))/(0.4ln(2))