What is the answer to \sqrt[x]{x}=\sqrt[4]{2} ?

The answer to \sqrt[x]{x}=\sqrt[4]{2} is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))

Solve for x: \sqrt[x]{x}=\sqrt[4]{2}

The solution is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))

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x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

Decimal Notation

x = 16, x = 1.23962 \dots

Solution steps

Apply exponent rules

\frac{1}{x} ln (x) = \frac{1}{4} ln (2)

Solve

\frac{1}{x} ln (x) = \frac{1}{4} ln (2) : x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

4^{x} = 2^{2 x}

e^{y} = 1

3^{2 (x + 1)} - 28 \cdot 3^{x} + 3 = 0

e^{- x} - e^{- x} x = 0

7^{x} = 21

What is the answer to \sqrt[x]{x}=\sqrt[4]{2} ?
The answer to \sqrt[x]{x}=\sqrt[4]{2} is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))
Solve for x: \sqrt[x]{x}=\sqrt[4]{2}
The solution is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))