What is the answer to 3^{7-2x}=(1/27)^{-8} ?

The answer to 3^{7-2x}=(1/27)^{-8} is x=-17/2

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3^{7-2x}=(1/27)^{-8}

3^{7 - 2 x} = (\frac{1}{27})^{- 8}

x = - \frac{17}{2}

Solution steps

3^{7 - 2 x} = (\frac{1}{27})^{- 8}

Apply exponent rules

7 - 2 x = 24

Solve

7 - 2 x = 24 : x = - \frac{17}{2}

x = - \frac{17}{2}

73 = 2 3^{x}

9^{x + 1} + 3 = 28 \cdot 3^{x}

4 9^{x} = 7

1 0^{x} + 5 = 60

e^{x - 1} - 5 = 5

What is the answer to 3^{7-2x}=(1/27)^{-8} ?
The answer to 3^{7-2x}=(1/27)^{-8} is x=-17/2
Solve for x: 3^{7-2x}=(1/27)^{-8}
The solution is x=-17/2