What is the answer to 1.1^x=2 ?

The answer to 1.1^x=2 is x=(ln(2))/(ln(1.1))

The solution is x=(ln(2))/(ln(1.1))

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1.1^x=2

1. 1^{x} = 2

x = \frac{ln ( 2 )}{ln ( 1.1 )}

Decimal Notation

x = 7.27254 \dots

Solution steps

1. 1^{x} = 2

Apply exponent rules

x ln (1.1) = ln (2)

Solve

x ln (1.1) = ln (2) : x = \frac{ln ( 2 )}{ln ( 1.1 )}

x = \frac{ln ( 2 )}{ln ( 1.1 )}

\frac{e ^{x + 5}}{e ^{5}} = 3

9^{x} - 3^{x + 1} + 2 = 0

e^{e^{x}} = 7

a^{x} = k b^{x}

2^{3 x - 5} = 3^{x + 3}