What is the answer to 2^{3x-5}=3^{x+3} ?

The answer to 2^{3x-5}=3^{x+3} is x=(ln(864))/(3ln(2)-ln(3))

Solve for x: 2^{3x-5}=3^{x+3}

The solution is x=(ln(864))/(3ln(2)-ln(3))

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2^{3 x - 5} = 3^{x + 3}

x = \frac{ln ( 864 )}{3 ln ( 2 ) - ln ( 3 )}

Solution steps

2^{3 x - 5} = 3^{x + 3}

Apply exponent rules

(3 x - 5) ln (2) = (x + 3) ln (3)

Solve

(3 x - 5) ln (2) = (x + 3) ln (3) : x = \frac{ln ( 864 )}{3 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 864 )}{3 ln ( 2 ) - ln ( 3 )}

k, k (x) = x^{6} e^{5 x}

(5 x)^{x} = 5^{5^{5}}

1 0^{l o g_{10} (x^{2})} = 4

3^{x + 4} = 5^{x + 2}

What is the answer to 2^{3x-5}=3^{x+3} ?
The answer to 2^{3x-5}=3^{x+3} is x=(ln(864))/(3ln(2)-ln(3))
Solve for x: 2^{3x-5}=3^{x+3}
The solution is x=(ln(864))/(3ln(2)-ln(3))