What is the answer to 3^{x+4}=5^{x+2} ?

The answer to 3^{x+4}=5^{x+2} is x=(4ln(3)-2ln(5))/(ln(5)-ln(3))

Solve for x: 3^{x+4}=5^{x+2}

The solution is x=(4ln(3)-2ln(5))/(ln(5)-ln(3))

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3^{x + 4} = 5^{x + 2}

x = \frac{4 ln ( 3 ) - 2 ln ( 5 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 2.30132 \dots

Solution steps

3^{x + 4} = 5^{x + 2}

Apply exponent rules

(x + 4) ln (3) = (x + 2) ln (5)

Solve

(x + 4) ln (3) = (x + 2) ln (5) : x = \frac{4 ln ( 3 ) - 2 ln ( 5 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{4 ln ( 3 ) - 2 ln ( 5 )}{ln ( 5 ) - ln ( 3 )}

9^{x} - 4 (3^{x}) + 3 = 0

e^{x} + 12 e^{- x} - 7 = 0

1 6^{2 x} = 8^{x - 1}

100 = \frac{300}{1 + e ^{4 - t}}

What is the answer to 3^{x+4}=5^{x+2} ?
The answer to 3^{x+4}=5^{x+2} is x=(4ln(3)-2ln(5))/(ln(5)-ln(3))
Solve for x: 3^{x+4}=5^{x+2}
The solution is x=(4ln(3)-2ln(5))/(ln(5)-ln(3))