What is the answer to solvefor x,2^x+8^y=16 ?

The answer to solvefor x,2^x+8^y=16 is x=(ln(16-2^{3y}))/(ln(2))

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solvefor x,2^x+8^y=16

solve for

x, 2^{x} + 8^{y} = 16

x = \frac{ln ( 16 - 2 ^{3 y} )}{ln ( 2 )}

Solution steps

2^{x} + 8^{y} = 16

Move

8^{y}

to the right side

2^{x} = 16 - 8^{y}

Apply exponent rules

x ln (2) = ln (16 - 2^{3 y})

Solve

x ln (2) = ln (16 - 2^{3 y}) : x = \frac{ln ( 16 - 2 ^{3 y} )}{ln ( 2 )}

x = \frac{ln ( 16 - 2 ^{3 y} )}{ln ( 2 )}

4^{x} = 100

2 7^{9 x + 4} \cdot 3^{x - 8} = 3^{x + 9}

2^{x} - 1 = 0

e^{2 x} = e^{x}

3^{x^{3}} = 9^{x}

What is the answer to solvefor x,2^x+8^y=16 ?
The answer to solvefor x,2^x+8^y=16 is x=(ln(16-2^{3y}))/(ln(2))