What is the answer to 5^{3x-1}=(1/25)^{2x+3} ?

The answer to 5^{3x-1}=(1/25)^{2x+3} is x=-5/7

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5^{3x-1}=(1/25)^{2x+3}

5^{3 x - 1} = (\frac{1}{25})^{2 x + 3}

x = - \frac{5}{7}

Decimal Notation

x = - 0.71428 \dots

Solution steps

5^{3 x - 1} = (\frac{1}{25})^{2 x + 3}

Apply exponent rules

3 x - 1 = - 2 (2 x + 3)

Solve

3 x - 1 = - 2 (2 x + 3) : x = - \frac{5}{7}

x = - \frac{5}{7}

(\frac{1}{3})^{x} = 52

\frac{9 ^{x^{2} - x}}{3 ^{3 x - 2}} = 1

4^{(1 - x)} = 3^{(2 x + 3)}

e^{e^{e^{x}}} = 15.1546741867000 \dots

e^{x - 3} + 1 = 4 x - 3

What is the answer to 5^{3x-1}=(1/25)^{2x+3} ?
The answer to 5^{3x-1}=(1/25)^{2x+3} is x=-5/7
Solve for x: 5^{3x-1}=(1/25)^{2x+3}
The solution is x=-5/7