What is the answer to 4^{x+2}=128^{1-x} ?

The answer to 4^{x+2}=128^{1-x} is x= 1/3

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4^{x+2}=128^{1-x}

4^{x + 2} = 12 8^{1 - x}

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

4^{x + 2} = 12 8^{1 - x}

Apply exponent rules

2 (x + 2) = 7 (1 - x)

Solve

2 (x + 2) = 7 (1 - x) : x = \frac{1}{3}

x = \frac{1}{3}

7^{2 y} = 3^{4}

ln (e^{x}) = x

e^{x^{2}} = 100

2^{x} - 4^{x} = - 12

\frac{3 ^{n - 2}}{9 ^{1 - n}} = 1

What is the answer to 4^{x+2}=128^{1-x} ?
The answer to 4^{x+2}=128^{1-x} is x= 1/3
Solve for x: 4^{x+2}=128^{1-x}
The solution is x= 1/3