What is the answer to 2(3^{4x-5})+4=11 ?

The answer to 2(3^{4x-5})+4=11 is x=(ln(1701/2))/(4ln(3))

Solve for x: 2(3^{4x-5})+4=11

The solution is x=(ln(1701/2))/(4ln(3))

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2 (3^{4 x - 5}) + 4 = 11

x = \frac{ln ( \frac{1701}{2} )}{4 ln ( 3 )}

Decimal Notation

x = 1.53507 \dots

Solution steps

2 (3^{4 x - 5}) + 4 = 11

Move

4

to the right side

2 \cdot 3^{4 x - 5} = 7

Divide both sides by

2

3^{4 x - 5} = \frac{7}{2}

Apply exponent rules

(4 x - 5) ln (3) = ln (\frac{7}{2})

Solve

(4 x - 5) ln (3) = ln (\frac{7}{2}) : x = \frac{ln ( \frac{1701}{2} )}{4 ln ( 3 )}

x = \frac{ln ( \frac{1701}{2} )}{4 ln ( 3 )}

\frac{50}{1 + e ^{- x}} = 4

4^{x^{2} + 4 x} = 2^{- 6}

8 1^{x - 3} = (\frac{1}{9})^{2 x - 1}

\frac{1}{25} = 5^{x + 4}

7^{x - 10} = 25

What is the answer to 2(3^{4x-5})+4=11 ?
The answer to 2(3^{4x-5})+4=11 is x=(ln(1701/2))/(4ln(3))
Solve for x: 2(3^{4x-5})+4=11
The solution is x=(ln(1701/2))/(4ln(3))