What is the answer to 5^x=21 ?

The answer to 5^x=21 is x=(ln(21))/(ln(5))

The solution is x=(ln(21))/(ln(5))

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5^x=21

5^{x} = 21

x = \frac{ln ( 21 )}{ln ( 5 )}

Solution steps

5^{x} = 21

Apply exponent rules

x ln (5) = ln (21)

Solve

x ln (5) = ln (21) : x = \frac{ln ( 21 )}{ln ( 5 )}

x = \frac{ln ( 21 )}{ln ( 5 )}

2^{x^{2}} = 8^{2 x - 3}

(\frac{1}{3})^{x + 2} = 3^{x - 1}

2^{x^{2} - x - 3} = \frac{1}{2}

5 \cdot 2^{3 x} = 15000

3^{8} = 9^{x}