What is the answer to (1/3)^{x+2}=3^{x-1} ?

The answer to (1/3)^{x+2}=3^{x-1} is x=-1/2

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(1/3)^{x+2}=3^{x-1}

(\frac{1}{3})^{x + 2} = 3^{x - 1}

x = - \frac{1}{2}

Solution steps

(\frac{1}{3})^{x + 2} = 3^{x - 1}

Apply exponent rules

- (x + 2) = x - 1

Solve

- (x + 2) = x - 1 : x = - \frac{1}{2}

x = - \frac{1}{2}

2^{x^{2} - x - 3} = \frac{1}{2}

5 \cdot 2^{3 x} = 15000

3^{8} = 9^{x}

9^{2 x - 1} = 3^{- x + 8}

4^{2 x - 1} = 3^{x + 2}

What is the answer to (1/3)^{x+2}=3^{x-1} ?
The answer to (1/3)^{x+2}=3^{x-1} is x=-1/2
Solve for x: (1/3)^{x+2}=3^{x-1}
The solution is x=-1/2