What is the answer to 6^{3x-5}=27 ?

The answer to 6^{3x-5}=27 is x=(3ln(3)+5ln(6))/(3ln(6))

Solve for x: 6^{3x-5}=27

The solution is x=(3ln(3)+5ln(6))/(3ln(6))

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6^{3 x - 5} = 27

x = \frac{3 ln ( 3 ) + 5 ln ( 6 )}{3 ln ( 6 )}

Solution steps

6^{3 x - 5} = 27

Apply exponent rules

(3 x - 5) ln (6) = ln (27)

Solve

(3 x - 5) ln (6) = ln (27) : x = \frac{3 ln ( 3 ) + 5 ln ( 6 )}{3 ln ( 6 )}

x = \frac{3 ln ( 3 ) + 5 ln ( 6 )}{3 ln ( 6 )}

5 (2^{x - 3}) = 4 (3^{x + 4})

8^{x} + 8^{x - 1} + 8^{x + 1} = 292

(n - 2)^{(n - 2) 2} = 2

2 x^{4} e^{- 2 x} = 0

4^{x + 3} = 64

What is the answer to 6^{3x-5}=27 ?
The answer to 6^{3x-5}=27 is x=(3ln(3)+5ln(6))/(3ln(6))
Solve for x: 6^{3x-5}=27
The solution is x=(3ln(3)+5ln(6))/(3ln(6))