What is the answer to 2^{x-6}=18 ?

The answer to 2^{x-6}=18 is x=(ln(18))/(ln(2))+6

Solve for x: 2^{x-6}=18

The solution is x=(ln(18))/(ln(2))+6

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2^{x - 6} = 18

x = \frac{ln ( 18 )}{ln ( 2 )} + 6

Solution steps

2^{x - 6} = 18

Apply exponent rules

(x - 6) ln (2) = ln (18)

Solve

(x - 6) ln (2) = ln (18) : x = \frac{ln ( 18 )}{ln ( 2 )} + 6

x = \frac{ln ( 18 )}{ln ( 2 )} + 6

12 \cdot 3^{- x} = \frac{4}{3}

2^{x + 1} + 2^{x + 2} = 96

e^{2 x} + 2 e^{2 x + 1} = 1 - e

1 6^{x - 1} = 2^{3 x + 2}

1 0^{\frac{2 z}{3}} = 15

What is the answer to 2^{x-6}=18 ?
The answer to 2^{x-6}=18 is x=(ln(18))/(ln(2))+6
Solve for x: 2^{x-6}=18
The solution is x=(ln(18))/(ln(2))+6