What is the answer to 3^{x+1}=5 ?

The answer to 3^{x+1}=5 is x=(ln(5))/(ln(3))-1

Solve for x: 3^{x+1}=5

The solution is x=(ln(5))/(ln(3))-1

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3^{x + 1} = 5

x = \frac{ln ( 5 )}{ln ( 3 )} - 1

Decimal Notation

x = 0.46497 \dots

Solution steps

3^{x + 1} = 5

Apply exponent rules

(x + 1) ln (3) = ln (5)

Solve

(x + 1) ln (3) = ln (5) : x = \frac{ln ( 5 )}{ln ( 3 )} - 1

x = \frac{ln ( 5 )}{ln ( 3 )} - 1

e^{- 4 x} - 5 e^{- 2 x} + 6 = 0

5^{3 x + 2} = 2 5^{x - 1}

3^{5 x} = 7^{1 - 5 x}

e^{t} = 1 + 6 e^{- t}

e^{5 x} = 5 e^{x}

What is the answer to 3^{x+1}=5 ?
The answer to 3^{x+1}=5 is x=(ln(5))/(ln(3))-1
Solve for x: 3^{x+1}=5
The solution is x=(ln(5))/(ln(3))-1