What is the answer to 6^{3x+1}=2^{2x-3} ?

The answer to 6^{3x+1}=2^{2x-3} is x=-(ln(48))/(ln(54))

Solve for x: 6^{3x+1}=2^{2x-3}

The solution is x=-(ln(48))/(ln(54))

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6^{3 x + 1} = 2^{2 x - 3}

x = - \frac{ln ( 48 )}{ln ( 54 )}

Solution steps

6^{3 x + 1} = 2^{2 x - 3}

Apply exponent rules

(3 x + 1) ln (6) = (2 x - 3) ln (2)

Solve

(3 x + 1) ln (6) = (2 x - 3) ln (2) : x = - \frac{ln ( 48 )}{ln ( 54 )}

x = - \frac{ln ( 48 )}{ln ( 54 )}

10 0^{x} = 1

3^{(x - 4)} = 7

(\frac{1}{4})^{x + 1} = 32

2 \cdot e^{- 6 w} = 95

3^{x} = 24

What is the answer to 6^{3x+1}=2^{2x-3} ?
The answer to 6^{3x+1}=2^{2x-3} is x=-(ln(48))/(ln(54))
Solve for x: 6^{3x+1}=2^{2x-3}
The solution is x=-(ln(48))/(ln(54))