What is the answer to e^{(x+1)^2}=9 ?

The answer to e^{(x+1)^2}=9 is x=sqrt(2)sqrt(ln(3))-1,x=-sqrt(2)sqrt(ln(3))-1

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e^{(x+1)^2}=9

e^{(x + 1)^{2}} = 9

x = 2 ln (3) - 1, x = - 2 ln (3) - 1

Decimal Notation

x = 0.48230 \dots, x = - 2.48230 \dots

Solution steps

e^{(x + 1)^{2}} = 9

Apply exponent rules

(x + 1)^{2} = ln (9)

Solve

(x + 1)^{2} = ln (9) : x = 2 ln (3) - 1, x = - 2 ln (3) - 1

x = 2 ln (3) - 1, x = - 2 ln (3) - 1

0.793 7^{x} = \frac{1.25}{10}

x, 4 = y^{2 x}

3^{4 x + 5} = 8 1^{- \frac{3}{4}}

4^{2 x} - 2^{2 x + 1} = 35

\frac{2 5 ^{x} + 125}{6} = 5^{x + 1}

What is the answer to e^{(x+1)^2}=9 ?
The answer to e^{(x+1)^2}=9 is x=sqrt(2)sqrt(ln(3))-1,x=-sqrt(2)sqrt(ln(3))-1