What is the answer to 3^{sqrt(x)}=6^{x^2} ?

The answer to 3^{sqrt(x)}=6^{x^2} is x=0,x=\sqrt[3]{(ln^2(3))/(ln^2(6))}

Solve for x: 3^{sqrt(x)}=6^{x^2}

The solution is x=0,x=\sqrt[3]{(ln^2(3))/(ln^2(6))}

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3^{x} = 6^{x^{2}}

Decimal Notation

x = 0, x = 0.72173 \dots

Solution steps

3^{x} = 6^{x^{2}}

Apply exponent rules

x ln (3) = x^{2} ln (6)

Solve

2^{x + 1} = \frac{1}{4}

2^{x + 4} - 12 = 20

b, a^{\frac{b}{4}} = 16

3^{x + 2} = 7^{x}

e^{x^{2}} = 312

What is the answer to 3^{sqrt(x)}=6^{x^2} ?
The answer to 3^{sqrt(x)}=6^{x^2} is x=0,x=\sqrt[3]{(ln^2(3))/(ln^2(6))}
Solve for x: 3^{sqrt(x)}=6^{x^2}
The solution is x=0,x=\sqrt[3]{(ln^2(3))/(ln^2(6))}