What is the answer to 2^x-2+2^{-x}=0 ?

The answer to 2^x-2+2^{-x}=0 is x=0

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2^x-2+2^{-x}=0

2^{x} - 2 + 2^{- x} = 0

x = 0

Solution steps

2^{x} - 2 + 2^{- x} = 0

Apply exponent rules

2^{x} - 2 + (2^{x})^{- 1} = 0

Rewrite the equation with

2^{x} = u

u - 2 + (u)^{- 1} = 0

Solve

u - 2 + u^{- 1} = 0 : u = 1

u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 1 : x = 0

x = 0

5^{x} = 11

y, x = 2^{- y}

r, t^{r} = 0

ln (e^{7 x}) = 15

x, y = 5 e^{2 x}