What is the answer to (1/3)^{2x+3}=5 ?

The answer to (1/3)^{2x+3}=5 is x=-(ln(135))/(2ln(3))

Solve for x: (1/3)^{2x+3}=5

The solution is x=-(ln(135))/(2ln(3))

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(\frac{1}{3})^{2 x + 3} = 5

x = - \frac{ln ( 135 )}{2 ln ( 3 )}

Decimal Notation

x = - 2.23248 \dots

Solution steps

(\frac{1}{3})^{2 x + 3} = 5

Apply exponent rules

(2 x + 3) ln (\frac{1}{3}) = ln (5)

Solve

(2 x + 3) ln (\frac{1}{3}) = ln (5) : x = - \frac{ln ( 135 )}{2 ln ( 3 )}

x = - \frac{ln ( 135 )}{2 ln ( 3 )}

8 + 0.04 x = 6 (1.02)^{x}

x^{10} = e^{x}

4^{x} = \frac{8}{1 6 ^{x}}

x, e^{x} = 4

2^{1 - x} = 3^{x}

What is the answer to (1/3)^{2x+3}=5 ?
The answer to (1/3)^{2x+3}=5 is x=-(ln(135))/(2ln(3))
Solve for x: (1/3)^{2x+3}=5
The solution is x=-(ln(135))/(2ln(3))