What is the answer to 2^{1-x}=3^x ?

The answer to 2^{1-x}=3^x is x=(ln(2))/(ln(6))

Solve for x: 2^{1-x}=3^x

The solution is x=(ln(2))/(ln(6))

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2^{1 - x} = 3^{x}

x = \frac{ln ( 2 )}{ln ( 6 )}

Solution steps

2^{1 - x} = 3^{x}

Apply exponent rules

(1 - x) ln (2) = x ln (3)

Solve

(1 - x) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{ln ( 6 )}

x = \frac{ln ( 2 )}{ln ( 6 )}

e^{x - 1} = 3^{\frac{2 x}{3}}

2^{(1 - x)} + 2^{(1 + x)} = 4

3^{x - 5} = 9

1 0^{x} = 18

What is the answer to 2^{1-x}=3^x ?
The answer to 2^{1-x}=3^x is x=(ln(2))/(ln(6))
Solve for x: 2^{1-x}=3^x
The solution is x=(ln(2))/(ln(6))