What is the answer to 2^{(1-x)}+2^{(1+x)}=4 ?

The answer to 2^{(1-x)}+2^{(1+x)}=4 is x=0

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2^{(1-x)}+2^{(1+x)}=4

2^{(1 - x)} + 2^{(1 + x)} = 4

x = 0

Solution steps

2^{(1 - x)} + 2^{(1 + x)} = 4

Apply exponent rules

(2^{x})^{- 1} \cdot 2^{1} + 2^{x} \cdot 2^{1} = 4

Rewrite the equation with

2^{x} = u

(u)^{- 1} \cdot 2^{1} + u \cdot 2^{1} = 4

Solve

u^{- 1} \cdot 2^{1} + u \cdot 2^{1} = 4 : u = 1

u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 1 : x = 0

x = 0

3^{x - 5} = 9

1 0^{x} = 18

2 = 1 4^{x + 2}

- x^{2} e^{- x} + 5 x e^{- x} = 0

What is the answer to 2^{(1-x)}+2^{(1+x)}=4 ?
The answer to 2^{(1-x)}+2^{(1+x)}=4 is x=0
Solve for x: 2^{(1-x)}+2^{(1+x)}=4
The solution is x=0