What is the answer to 2=14^{x+2} ?

The answer to 2=14^{x+2} is x=(ln(2))/(ln(14))-2

Solve for x: 2=14^{x+2}

The solution is x=(ln(2))/(ln(14))-2

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2 = 1 4^{x + 2}

x = \frac{ln ( 2 )}{ln ( 14 )} - 2

Decimal Notation

x = - 1.73735 \dots

Solution steps

2 = 1 4^{x + 2}

Apply exponent rules

ln (2) = (x + 2) ln (14)

Solve

ln (2) = (x + 2) ln (14) : x = \frac{ln ( 2 )}{ln ( 14 )} - 2

x = \frac{ln ( 2 )}{ln ( 14 )} - 2

- x^{2} e^{- x} + 5 x e^{- x} = 0

3^{2 x + 2} + 3 (3^{x}) - 2 = 0

5^{x - 3} = 137

1 0^{2 x^{2} + 2 x} = 10 0^{- 6 x + 8}

(2 e)^{(x^{2} - 2)} = 4

What is the answer to 2=14^{x+2} ?
The answer to 2=14^{x+2} is x=(ln(2))/(ln(14))-2
Solve for x: 2=14^{x+2}
The solution is x=(ln(2))/(ln(14))-2