What is the answer to 8^{-2-x}=431 ?

The answer to 8^{-2-x}=431 is x=-(ln(431)+6ln(2))/(3ln(2))

Solve for x: 8^{-2-x}=431

The solution is x=-(ln(431)+6ln(2))/(3ln(2))

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8^{- 2 - x} = 431

x = - \frac{ln ( 431 ) + 6 ln ( 2 )}{3 ln ( 2 )}

Decimal Notation

x = - 4.91718 \dots

Solution steps

8^{- 2 - x} = 431

Apply exponent rules

(- 2 - x) ln (8) = ln (431)

Solve

(- 2 - x) ln (8) = ln (431) : x = - \frac{ln ( 431 ) + 6 ln ( 2 )}{3 ln ( 2 )}

x = - \frac{ln ( 431 ) + 6 ln ( 2 )}{3 ln ( 2 )}

6^{x + 3} = 3^{x}

0.5 \cdot 1 0^{8 t} = 73

4^{x} = 6^{1 - x}

5^{3 x + 2} + 3 \cdot 5^{6 x + 2} - 100 = 0

3^{5 x + 2} = 21

What is the answer to 8^{-2-x}=431 ?
The answer to 8^{-2-x}=431 is x=-(ln(431)+6ln(2))/(3ln(2))
Solve for x: 8^{-2-x}=431
The solution is x=-(ln(431)+6ln(2))/(3ln(2))