What is the answer to 3^{x-1}=2 ?

The answer to 3^{x-1}=2 is x=(ln(2))/(ln(3))+1

Solve for x: 3^{x-1}=2

The solution is x=(ln(2))/(ln(3))+1

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3^{x - 1} = 2

x = \frac{ln ( 2 )}{ln ( 3 )} + 1

Decimal Notation

x = 1.63092 \dots

Solution steps

3^{x - 1} = 2

Apply exponent rules

(x - 1) ln (3) = ln (2)

Solve

(x - 1) ln (3) = ln (2) : x = \frac{ln ( 2 )}{ln ( 3 )} + 1

x = \frac{ln ( 2 )}{ln ( 3 )} + 1

3 = 4^{x}

2 e^{x} + 3 e^{- x} = 7

8^{x} = \frac{1}{2}

8 1^{x} = 243

3^{x + 1} = 4

What is the answer to 3^{x-1}=2 ?
The answer to 3^{x-1}=2 is x=(ln(2))/(ln(3))+1
Solve for x: 3^{x-1}=2
The solution is x=(ln(2))/(ln(3))+1