What is the answer to 3^{x+1}=4 ?

The answer to 3^{x+1}=4 is x=(2ln(2))/(ln(3))-1

Solve for x: 3^{x+1}=4

The solution is x=(2ln(2))/(ln(3))-1

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3^{x + 1} = 4

x = \frac{2 ln ( 2 )}{ln ( 3 )} - 1

Decimal Notation

x = 0.26185 \dots

Solution steps

3^{x + 1} = 4

Apply exponent rules

(x + 1) ln (3) = ln (4)

Solve

(x + 1) ln (3) = ln (4) : x = \frac{2 ln ( 2 )}{ln ( 3 )} - 1

x = \frac{2 ln ( 2 )}{ln ( 3 )} - 1

3^{x} \cdot 2^{2 x - 3} = 18

4^{x + 1} = \frac{1}{64}

y, x = e^{2 y - 1}

5^{2 x} - 26 \cdot 5^{x} + 25 = 0

9^{x} - 3^{x} = 72

What is the answer to 3^{x+1}=4 ?
The answer to 3^{x+1}=4 is x=(2ln(2))/(ln(3))-1
Solve for x: 3^{x+1}=4
The solution is x=(2ln(2))/(ln(3))-1