What is the answer to 4^{x^2}=2^{x+3} ?

The answer to 4^{x^2}=2^{x+3} is x= 3/2 ,x=-1

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4^{x^2}=2^{x+3}

4^{x^{2}} = 2^{x + 3}

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

4^{x^{2}} = 2^{x + 3}

Apply exponent rules

2 x^{2} = x + 3

Solve

2 x^{2} = x + 3 : x = \frac{3}{2}, x = - 1

x = \frac{3}{2}, x = - 1

9^{x} - 4 \cdot 3^{x} + 3 = 0

8^{3 x} = 1 6^{2 x - 4}

6^{x} = 7776

5^{x + 1} = 2 (3^{2 x})

4^{2 p} = 4^{- 2 p - 1}

What is the answer to 4^{x^2}=2^{x+3} ?
The answer to 4^{x^2}=2^{x+3} is x= 3/2 ,x=-1
Solve for x: 4^{x^2}=2^{x+3}
The solution is x= 3/2 ,x=-1