What is the answer to 20*7^{3y}=5 ?

The answer to 20*7^{3y}=5 is y=-(2ln(2))/(3ln(7))

Solve for y: 20*7^{3y}=5

The solution is y=-(2ln(2))/(3ln(7))

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20 \cdot 7^{3 y} = 5

y = - \frac{2 ln ( 2 )}{3 ln ( 7 )}

Solution steps

20 \cdot 7^{3 y} = 5

Divide both sides by

20

7^{3 y} = \frac{1}{4}

Apply exponent rules

3 y ln (7) = ln (\frac{1}{4})

Solve

3 y ln (7) = ln (\frac{1}{4}) : y = - \frac{2 ln ( 2 )}{3 ln ( 7 )}

y = - \frac{2 ln ( 2 )}{3 ln ( 7 )}

1 = 4^{x}

4^{x + 2} = 12

5^{9 x + 5} = 2

y, x = e^{y} - e^{- y}

6 \cdot 2^{\frac{x}{4}} = 222

What is the answer to 20*7^{3y}=5 ?
The answer to 20*7^{3y}=5 is y=-(2ln(2))/(3ln(7))
Solve for y: 20*7^{3y}=5
The solution is y=-(2ln(2))/(3ln(7))