What is the answer to 3^{7x+4}=(1/27)^{x-3} ?

The answer to 3^{7x+4}=(1/27)^{x-3} is x= 1/2

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3^{7x+4}=(1/27)^{x-3}

3^{7 x + 4} = (\frac{1}{27})^{x - 3}

x = \frac{1}{2}

Solution steps

3^{7 x + 4} = (\frac{1}{27})^{x - 3}

Apply exponent rules

7 x + 4 = - 3 (x - 3)

Solve

7 x + 4 = - 3 (x - 3) : x = \frac{1}{2}

x = \frac{1}{2}

e^{4 - 4 x} = 5

1 0^{x + 8} = 36

x, e^{x} (y - 2) = y

3^{x^{2} + x} = 3

e^{2 t - 1} - 3 = 0

What is the answer to 3^{7x+4}=(1/27)^{x-3} ?
The answer to 3^{7x+4}=(1/27)^{x-3} is x= 1/2
Solve for x: 3^{7x+4}=(1/27)^{x-3}
The solution is x= 1/2