What is the answer to 20^{x-9}=12 ?

The answer to 20^{x-9}=12 is x=(ln(12))/(ln(20))+9

Solve for x: 20^{x-9}=12

The solution is x=(ln(12))/(ln(20))+9

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2 0^{x - 9} = 12

x = \frac{ln ( 12 )}{ln ( 20 )} + 9

Decimal Notation

x = 9.82948 \dots

Solution steps

2 0^{x - 9} = 12

Apply exponent rules

(x - 9) ln (20) = ln (12)

Solve

(x - 9) ln (20) = ln (12) : x = \frac{ln ( 12 )}{ln ( 20 )} + 9

x = \frac{ln ( 12 )}{ln ( 20 )} + 9

1 0^{\frac{3 x - 1}{2 x + 1}} = 100

0.2 e^{4 x} - 0.1 e^{- 3 x} = 0

(1 4^{3 x + 1}) (8^{2 x + 3}) = 7

5^{x} = 22

5^{x} = 23

What is the answer to 20^{x-9}=12 ?
The answer to 20^{x-9}=12 is x=(ln(12))/(ln(20))+9
Solve for x: 20^{x-9}=12
The solution is x=(ln(12))/(ln(20))+9