What is the answer to 4^{(2x^2+x-6)}=1 ?

The answer to 4^{(2x^2+x-6)}=1 is x= 3/2 ,x=-2

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4^{(2x^2+x-6)}=1

4^{(2 x^{2} + x - 6)} = 1

x = \frac{3}{2}, x = - 2

Decimal Notation

x = 1.5, x = - 2

Solution steps

4^{(2 x^{2} + x - 6)} = 1

Apply exponent rules

(2 x^{2} + x - 6) ln (4) = ln (1)

Solve

(2 x^{2} + x - 6) ln (4) = ln (1) : x = \frac{3}{2}, x = - 2

x = \frac{3}{2}, x = - 2

t, a = p (1 + r)^{t}

(\frac{1}{16})^{x - 2} = 64

10 0^{x + 3} = \frac{1}{10}

2^{x} = 4^{3}

\frac{1}{e ^{x}} = 0

What is the answer to 4^{(2x^2+x-6)}=1 ?
The answer to 4^{(2x^2+x-6)}=1 is x= 3/2 ,x=-2
Solve for x: 4^{(2x^2+x-6)}=1
The solution is x= 3/2 ,x=-2