What is the answer to solvefor t,a=p(1+r)^t ?

The answer to solvefor t,a=p(1+r)^t is t=(ln(a/p))/(ln(1+r))

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solvefor t,a=p(1+r)^t

solve for

t, a = p (1 + r)^{t}

t = \frac{ln ( \frac{a}{p} )}{ln ( 1 + r )}

Solution steps

a = p (1 + r)^{t}

Switch sides

p (1 + r)^{t} = a

Divide both sides by

p

(1 + r)^{t} = \frac{a}{p}

Apply exponent rules

t ln (1 + r) = ln (\frac{a}{p})

Solve

t ln (1 + r) = ln (\frac{a}{p}) : t = \frac{ln ( \frac{a}{p} )}{ln ( 1 + r )}

t = \frac{ln ( \frac{a}{p} )}{ln ( 1 + r )}

(\frac{1}{16})^{x - 2} = 64

10 0^{x + 3} = \frac{1}{10}

2^{x} = 4^{3}

\frac{1}{e ^{x}} = 0

4^{x} + 2^{1 + 2 x} = 40

What is the answer to solvefor t,a=p(1+r)^t ?
The answer to solvefor t,a=p(1+r)^t is t=(ln(a/p))/(ln(1+r))