What is the answer to 4^x+2^{1+2x}=40 ?

The answer to 4^x+2^{1+2x}=40 is x=(ln(40/3))/(2ln(2))

Solve for x: 4^x+2^{1+2x}=40

The solution is x=(ln(40/3))/(2ln(2))

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4^{x} + 2^{1 + 2 x} = 40

x = \frac{ln ( \frac{40}{3} )}{2 ln ( 2 )}

Decimal Notation

x = 1.86848 \dots

Solution steps

4^{x} + 2^{1 + 2 x} = 40

Apply exponent rules

2 x ln (2) = ln (\frac{40}{3})

Solve

2 x ln (2) = ln (\frac{40}{3}) : x = \frac{ln ( \frac{40}{3} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{40}{3} )}{2 ln ( 2 )}

3^{2 x} - 3^{x} - 6 = 0

3^{x} + 3^{x + 2} = 90

1 0^{x} = 31

1 0^{x} = 87

2 5^{3 x + 2} = 125

What is the answer to 4^x+2^{1+2x}=40 ?
The answer to 4^x+2^{1+2x}=40 is x=(ln(40/3))/(2ln(2))
Solve for x: 4^x+2^{1+2x}=40
The solution is x=(ln(40/3))/(2ln(2))