What is the answer to 2^x=5^{x-1} ?

The answer to 2^x=5^{x-1} is x=(ln(5))/(ln(5)-ln(2))

Solve for x: 2^x=5^{x-1}

The solution is x=(ln(5))/(ln(5)-ln(2))

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2^{x} = 5^{x - 1}

x = \frac{ln ( 5 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 1.75647 \dots

Solution steps

2^{x} = 5^{x - 1}

Apply exponent rules

x ln (2) = (x - 1) ln (5)

Solve

x ln (2) = (x - 1) ln (5) : x = \frac{ln ( 5 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 5 ) - ln ( 2 )}

t, a = b^{t}

4^{x} = 4

3^{x} + 1 = 10

8^{x - 1} = 1 6^{3 x}

0.5 = 2^{x}

What is the answer to 2^x=5^{x-1} ?
The answer to 2^x=5^{x-1} is x=(ln(5))/(ln(5)-ln(2))
Solve for x: 2^x=5^{x-1}
The solution is x=(ln(5))/(ln(5)-ln(2))