What is the answer to 2*3^k=12 ?

The answer to 2*3^k=12 is k=(ln(6))/(ln(3))

Solve for k: 2*3^k=12

The solution is k=(ln(6))/(ln(3))

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2 \cdot 3^{k} = 12

k = \frac{ln ( 6 )}{ln ( 3 )}

Decimal Notation

k = 1.63092 \dots

Solution steps

2 \cdot 3^{k} = 12

Divide both sides by

2

3^{k} = 6

Apply exponent rules

k ln (3) = ln (6)

Solve

k ln (3) = ln (6) : k = \frac{ln ( 6 )}{ln ( 3 )}

k = \frac{ln ( 6 )}{ln ( 3 )}

e^{x - 4} + 2.5 x - 11.7 = 0

k, n^{l o g_{10} (n)} = n^{k}

x, 2^{x} = 6

2^{(1 - x^{2})} = \frac{1}{8}

2^{x + 1} = 4