What is the answer to 6^{x+1}-18*6^{x-1}=108 ?

The answer to 6^{x+1}-18*6^{x-1}=108 is x=2

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6^{x+1}-18*6^{x-1}=108

6^{x + 1} - 18 \cdot 6^{x - 1} = 108

x = 2

Solution steps

6^{x + 1} - 18 \cdot 6^{x - 1} = 108

Factor

6^{x + 1} - 18 \cdot 6^{x - 1} : 2^{x} \cdot 3^{x + 1}

2^{x} \cdot 3^{x + 1} = 108

Apply exponent rules

x = 2

2^{3 x + 2} = 6

1 0^{x + 2} - 12 = 22

2^{x} = A^{\frac{x}{12}}

86 \cdot 1 0^{\frac{x}{4}} = 41

8^{x + 6} = 5^{x}

What is the answer to 6^{x+1}-18*6^{x-1}=108 ?
The answer to 6^{x+1}-18*6^{x-1}=108 is x=2
Solve for x: 6^{x+1}-18*6^{x-1}=108
The solution is x=2