What is the answer to 7=2^x ?

The answer to 7=2^x is x=(ln(7))/(ln(2))

The solution is x=(ln(7))/(ln(2))

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7=2^x

7 = 2^{x}

x = \frac{ln ( 7 )}{ln ( 2 )}

Decimal Notation

x = 2.80735 \dots

Solution steps

7 = 2^{x}

Apply exponent rules

ln (7) = x ln (2)

Solve

ln (7) = x ln (2) : x = \frac{ln ( 7 )}{ln ( 2 )}

x = \frac{ln ( 7 )}{ln ( 2 )}

3 e^{2 x} = 4

(3 π)^{p} = 27 π^{3}

4^{x + 3} = 8^{x + 5}

8^{7 x + 8} = 3

8 1^{x^{2 - 1}} = 2 7^{- (7 - 5 x)}