What is the answer to 36^{5x+2}=(1/6)^{11-x} ?

The answer to 36^{5x+2}=(1/6)^{11-x} is x=-5/3

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36^{5x+2}=(1/6)^{11-x}

3 6^{5 x + 2} = (\frac{1}{6})^{11 - x}

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

3 6^{5 x + 2} = (\frac{1}{6})^{11 - x}

Apply exponent rules

2 (5 x + 2) = - (11 - x)

Solve

2 (5 x + 2) = - (11 - x) : x = - \frac{5}{3}

x = - \frac{5}{3}

(9 x)^{x} = 9^{3^{18}}

8 (2^{2 x}) - 10 (2^{x}) + 2 = 0

(2)^{x} = 4^{x^{2} + 1}

2^{2 x} + 2^{x + 2} - 12 = 0

- x e^{- x} + e^{- x} = 0

What is the answer to 36^{5x+2}=(1/6)^{11-x} ?
The answer to 36^{5x+2}=(1/6)^{11-x} is x=-5/3
Solve for x: 36^{5x+2}=(1/6)^{11-x}
The solution is x=-5/3