What is the answer to 4^{3x+1}=8^{x-1} ?

The answer to 4^{3x+1}=8^{x-1} is x=-5/3

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4^{3x+1}=8^{x-1}

4^{3 x + 1} = 8^{x - 1}

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

4^{3 x + 1} = 8^{x - 1}

Apply exponent rules

2 (3 x + 1) = 3 (x - 1)

Solve

2 (3 x + 1) = 3 (x - 1) : x = - \frac{5}{3}

x = - \frac{5}{3}

9^{2 x - 3} = 27

4 \cdot 3^{4 x + 1} = 2

e^{2 x} - 8 e^{x} + 12 = 0

2^{x} = 4 x

\frac{1}{2} = 2^{x}

What is the answer to 4^{3x+1}=8^{x-1} ?
The answer to 4^{3x+1}=8^{x-1} is x=-5/3
Solve for x: 4^{3x+1}=8^{x-1}
The solution is x=-5/3